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Secondary Current Injection Kit

Model
Nature of the Manufacturer
Manufacturer
Product Category
Relay Test Set
Place of Origin
City, Province
Overview
AC current output :6 channels ,30 A/450VA 6 parallel A/1000VA eachAC voltage output :6 channels ,120 V/80VA line voltage 240 V/120VA eachAC output accuracy :0.1%(within main range)DC current output :6 channels ,10 A/120VA ± eachDC voltage output :6 channels ,160 V/80VA ± eachDC output accuracy :0.2%(within main range)
Product Details
1.Feature


1.1 High-speed, high-capacity industrial control computer ,10.4" super screen.

Built-in embedded Windows XPE operating system, software system is highly stable, electronic hard disk capacity, any switch machine, no system damage. The device comes with a 10.4" large screen, large display capacity and font, good effect.

1.2 Standard 12 phase voltage and current output at the same time, and amplitude, phase, frequency completely independent regulation.

1.3 Closed-loop recovery recording monitoring of 12 channels

The output waveform of 12 channel voltage and current of this machine is mined, monitored and recorded. The output waveform distortion can be monitored and observed directly and conveniently.

1.4.Dual operation mode

In addition to the single machine operation, the device can also be connected to a desktop computer or notebook computer to operate, the two modes of function are completely consistent, truly complete dual operation mode.

1.5High performance master controller

The output part is controlled by ultra-high speed DSP FPGA, the real-time signal processing ability is very strong, the transmission frequency bandwidth is very strong, and the output of 2400 high precision waveforms per week is 18 bit DA converter. The output waveform has high precision, low distortion and good linearity.

1.6 Structure of modular composite components

By using military technology, multistage insulation isolation and equipotential electrostatic shielding protection are realized, a large number of precision components are used, and specialized structural design is carried out. High reliability, excellent EMC performance, small size, light weight, full function, easy to carry.

1.7 New high fidelity linear amplifier

The output always uses high fidelity, high reliability modular linear power amplifier, not switch power amplifier, small signal accuracy is extremely high, waveform exquisite smooth, excellent performance. It will not cause medium and high frequency interference to the test site, and ensure that the waveform is smooth and accurate from high current to micro current all the time

1.8 powerful function

It can complete all kinds of large and complex verification work with high degree of automation, can easily test and scan all kinds of protection values, carry out fault playback, store test data in real time, display vector diagram, print report online and so on. The 6-phase current can be easily tested for three-phase differential protection and the 12-phase output can be used for self-input testing

1.9 Ready for self-cast testing and fast cutting

Open 10 way 8 pairs out, can test a variety of self-input and fast cutting device. The design of the test interface is beautiful, and it can directly display the main wiring diagram of various systems, the state of each switch contact point, and the amplitude of current and voltage. It is very intuitive and convenient to test, record and display the whole operation process of the standby self-cast device

2.0 Rich contacts

10-way contact input and 8-pair empty contact output. The input contact is compatible with 0~250 V potential contact, which can be recognized intelligently and automatically. Input and output contacts can be extended according to user needs.

2.1 Independent adjustable DC power supply

Outputs with a dedicated DC power supply of 110 V or 220 V

2.2 Interface integrity

The device panel has its own keyboard and mouse, a single machine can complete operation. The device has USB port and network port, can communicate with the PC machine to operate, can be connected to the printer, keyboard, mouse, U disk and so on.

2.3 Built-in GPS

Equipped with GPS interface, the device can realize two-machine synchronous test and optical fiber longitudinal differential protection test.

2.4 Perfect self-protection function

The design of heat dissipation structure is reasonable, the hardware protection measures are reliable and perfect, it has the function of soft start of power supply, self-diagnosis of fault by software and the function of output locking

2.5 Light, small and high integrated single machine and integrated structure

Belong to cross-professional joint design products, comprehensive multi-professional advanced scientific and technological achievements. Small size, light weight, high performance-price ratio。

Hot tags: relay test kit,secondary injection test kit,secondary injection relay test kit,protection relay test kit,secondary current injection kit


II. Function and Application

This model secondary current injection kit has powerful functions, it is the latest advance model in our company. In addition to the verification of various relays (such as current, voltage, reverse time limit, power direction, impedance, differential, low cycle, synchronization, frequency, DC, intermediate, time, etc.) and microcomputer protection, the whole group test can be carried out to simulate the transient, permanent and conversion faults of single phase to three phase. It can also complete all kinds of large and complex verification work with high degree of automation, can automatically test and scan all kinds of protection values, carry out fault playback, test standby, fast cutting, system oscillation, etc., store test data in real time, display vector diagram, print report online, etc. The 6-phase current can be easily tested for three-phase differential protection and the 12-phase output can be used for self-input testing.


III. Main parameter


3.1 AC current output :6 channels ,30 A/450VA 6 parallel A/1000VA each

3.2 AC voltage output :6 channels ,120 V/80VA line voltage 240 V/120VA each

3.2 AC output accuracy :0.1%(within main range)

3.4 DC current output :6 channels ,10 A/120VA ± each

3.5 DC voltage output :6 channels ,160 V/80VA ± each

3.6 DC output accuracy :0.2%(within main range)

3.7 Phase :0~360

3.8 Phase accuracy :0.01

3.9 Superimposed harmonics :2~24 harmonics

4.0 Output frequency :0~1200 Hz

4.1 Frequency accuracy :0.001 Hz

4.2 Entry :10(nonpolar, extensible)

4.3 Outflow :8 pairs (expandable)

4.4 Independent DC: DC110V/220V, rated current 1.5 A

4.5 Size :420×360×210 mm3

4.6 Weight :19 kg


IV. Panel details


GPS can be configured according to client’s requirement.


Knowledge of microcomputer transformer differential protection


(1) Transformer connection

The transformer connection type of protection setting is the actual wiring of primary side of transformer, which has the type of Y / ∆-11, Y / Y(Y0), Y / ∆-1 and so on. For the three volume change in the test, the two volumes of them are generally taken out to test and the method of two volumes is the same.

(2) The balance coefficient of high-pressure side

At present, most microcomputer protection always adopts the way of calculation to make the data and phase of Y-∆ self-correction in the internal protection. Therefore, the external connection is simpler, although the transformer is Y/∆-11 connection and the CT is Y/Y connection. Of course, there is also a part of the microcomputer protection is not so, which is still CT connection of transformer is corrected.

The setting value of differential protection does not have the balance coefficient of high-pressure side, which brings inconvenience to the test and calculation. We know that the balance coefficient of high-pressure side is 1 by default, but the actual value of balance coefficient is often measured as 1.732. The balance coefficient of high-pressure side can be got as the following method.

In the differential threshold and instantaneous value test, if the actual value of action current is equal to 1.732 times of the setting value, the balance coefficient of high-pressure side is set to 1.732 when computing. If the actual value of action current is equal to the setting value, the balance coefficient of high-pressure side is set to 1 when computing.

(3) The wiring method in the test

When the transformer connection type is Y / Y (Y0), the test wiring is simple. When testing the phase A, the IA of tester is connect with the phase A of high-pressure side and the IB of tester is connect with the phase a of low-pressure side. After the the neutral line of the high and low pressure side shorted, connect with the IN of tester and there does not exsist the problem of the compensation current. If the phase B or phase C is tested, the wiring is similar to the above.

When the transformer connection type is Y / ∆-11, the common wiring is that when testing the phase A, the IA of tester is connect with the phase A of high-pressure side and the IB , IC of tester is respectively connect with the phase a, phase c of low-pressure side. After the the neutral line of the high and low pressure side shorted, connect with the IN of tester and the IC is set as compensation current. But how is it to wiring if the phase B or phase C is asked to be tested.

4

As shown by the vector map on the right, the current of high voltage side after conversion should be I'A = ( IA - IB ) / 1.732,I'B = ( IB - IC ) / 1.732,I'C = ( IC - IA ) / 1.732. If phase A of high-pressure side is provided a current value and phase B, phase C are not provided, the three-phase current of high-pressure side after conversion should be as below.

I'A = ( IA - IB ) / 1.732 = ( IA - 0) / 1.732 = IA / 1.732;

I'B = ( IB - IC ) / 1.732 = ( 0 - 0 ) / 1.732 = 0;

I'C = ( IC - IA ) / 1.732 = ( 0 - IA ) / 1.732 = - IA / 1.732.

So phase C of high-pressure side is provided a current value, which is equal to the value of phase A and the direction is opposite. During the experiment, in order to balance the current value of phase C of high-pressure side, phase c of low-pressure side should be provided compensation current. And the value of compensation current should be equal to the value of phase a of low-pressure side and the direction is opposite

Similarly, if the phase B of test transformer, the pahse B of high-pressure side should be provided a current value and the phase A or phase C is not provided. According to the above formula, we can get as below.

I'A = ( IA - IB ) / 1.732 = ( 0 - IB) / 1.732 = -IB / 1.732;

I'B = ( IB - IC ) / 1.732 = ( IB - 0 ) / 1.732 = IB / 1.732;

I'C = ( IC - IA ) / 1.732 = ( 0 - 0 ) / 1.732 = 0.

This shows that the pahse A of high-pressure side has an equal and opposite current and phase a of low-pressure side should be compensated in the test. Therefore, the correct wiring is that the IA of tester is connect with the phase B of high-pressure side and the IB , IC of tester is respectively connect with the phase B, phase a of low-pressure side. After the the neutral line of the high and low pressure side shorted, connect with the IN of tester and the IC is set as compensation current.

Considering the two current of low-pressure side has the characteristics of ‘equal and opposite’, the two current for protection can be provided in the test. The correct wiring is that the IA of tester is connect with the phase A of high-pressure side and the IB of tester is connect with the phase a of low-pressure side and the phase a, C negative terminal of protcteion low-pressure side should be shorted. After the phase c of low-pressure side and the the neutral line of the high and low pressure side shorted, connect with the IN of tester.

From the above analysis is not difficult to find that the current value of the protection low-pressure side should have the opposite with the current value of the high-pressure side and the compensation current value of the low-pressure side should have the opposite with the corresponding current value of the low-pressure side. So when the phase A of transformer is tested and the IA of tester is set to 0º, the current value of IB ,IC of tester should be respectively set to 180º, 0º.

(4) The action equation of protection

Suppose that the differential current of protection is set as Ir, the differential current threshold value is set as Icd, the differential speed concluded value is Isd, inflection point 1 is Ig1, the braking coefficient of proportion is K1, inflection point 2 is Ig2, the braking coefficient of proportion is K2, the vast majority of action equations of protection in china is shown as below.

Id > Icd when Ir < Ig;

Id > Icd + K * ( Ir – Ig1 ) when Ig2 > Ir > Ig1;

Id > Icd + K1 * ( Ig2 – Ig1 ) + K2 *( Ir – Ig2) when Ir > Ig2;

Id > Isd

The proportion of braking curve is as shown on the right.

5

As long as one of the above four action equations is satisified, the action of protection will be exported.

At present, most differential protection olny use a inflection point.Even the differential protection has two inflection points, in order to test more convenient and simple, the setting value of protection is often modified as that Ig1 = Ig2;K1 = K2, which can make it be tested by the method of one inflection point. The action equation of proportional braking which has only one one inflection point is as following.

Id > Icd + K * ( Ir – Ig ) when Ir > Ig;

For the microcomputer differential protection, in fact, the proportion of braking and speed concluded protection is two sets of protection. So many of the protections are set up control word to cast or back the two protections.

No matter the proportion of braking protection or speed concluded protection, the export action time of them is short, which is generally between 30ms and 60ms. They often share a common exit port which brings some inconvenience to the test. Generally, the protection of ‘proportion of braking’ should be exit by the control word when test the differential protection of speed concluded. If not or some protection do not have this function, the output current should be increased after the proportion of braking protection operating to judge whether the differential protection of speed concluded.quickly operate or not by the light of protection or the relevant report.

(5) The relationship between the current value of high and low press side and the value of differential current and braking current

It is worth noting that, during the test, by changing a phase current of tester to make the protection operate, the output current of tester is not action current or braking current and can not influence by the the action principle of differential relays, which will take it for granted that the current of high-pressure side is action current and current of low-pressure side is braking current. The microcomputer differential protection does not directly compare the action current value of the high-pressure side with the action current value of the low-pressure side. It always judge whether has meet the above action equation. What is the relationship between the current value of high and low press side and the value of differential current and braking current?

In general, the differential current of protection in china are always use the equation that Id = | Ih + Il |, which can be expressed that the value of differential current is equal to and absolute value of the high and low pressure side of vector sum. Therefore, the current direction of the high and low pressure side must be paid attention.

The equations of the braking current often vary between the brand and model, and the most common formula of protection has three kinds in china as below.

1. Ir = max {Ih Il | |, | |}. The correct expression is that the vaule of braking current is equal to the maximum current amplitude of high and low pressure side.

2. Ir = ( | Ih | + | Il | ) / K. The correct expression is that the vaule of braking current is equal to the 1/K times the sum of current amplitude of high and low pressure side.

3. Ir = Ir = | Il |. The correct expression is that the vaule of braking current is equal to the current amplitude of high and low pressure side.

In the formula 2, the value of K in the mostly protection is 2, and in the individual protection is 1.

Besides, The other two formulas will also adopt the equation that Ir = | Ih - Il | / K, Ir =( | Id | - | Ih | - | Il | )/ K.

In fact, the value value of IA, IB output by tester cannot equal to the current value of high and low pressure side when the critical protection operating is record in the test. The balance coefficient of high and low pressure side should be considered. Assume that the IA of tester output to the high-pressure side, the IB of tester output to the low-pressure side, the balance coefficient of high and low pressure side is respectively K1, K2. The current of high-pressure side is set to Ih = K1 * IA, Il = K2 * IB. Then use the formula of differential current and braking current to calculate the differential current and braking current.


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Service Process



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4. If necessary, we will arrange for professional technical engineers to provide you with video, telephone contact and on-site commissioning services as agreed with you.

5. The engineer will explain to you in detail about product’s working theory and operation.

6. The engineer will guide you to finish the whole test process by video or on-site ,and give professional answers to your technical questions.

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